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don't fail with EINTR in sigtimedwait

POSIX allows either behavior, but sigwait is not allowed to fail with
EINTR, so the retry loop would have to be in one or the other anyway.
Rich Felker пре 14 година
родитељ
комит
0a949ebdf0
1 измењених фајлова са 6 додато и 6 уклоњено
  1. 6 6
      src/signal/sigtimedwait.c

+ 6 - 6
src/signal/sigtimedwait.c

@@ -1,12 +1,12 @@
 #include <signal.h>
+#include <errno.h>
 #include "syscall.h"
 
 int sigtimedwait(const sigset_t *mask, siginfo_t *si, const struct timespec *timeout)
 {
-	long k_timeout[2];
-	if (timeout) {
-		k_timeout[0] = timeout->tv_sec;
-		k_timeout[1] = timeout->tv_nsec;
-	}
-	return syscall4(__NR_rt_sigtimedwait, (long)mask, (long)si, timeout ? (long)k_timeout : 0, SYSCALL_SIGSET_SIZE);
+	int ret;
+	do {
+		ret = syscall4(__NR_rt_sigtimedwait, (long)mask, (long)si, (long)timeout, SYSCALL_SIGSET_SIZE);
+	} while (ret<0 && errno==EINTR);
+	return ret;
 }