Forráskód Böngészése

sqrtl: fix invalid use of a non-constant-expression as static initializer

having these constants be static was unnecessary, so just remove the
static.

this error should have been caught by compilers, but recent versions
of both gcc and clang accept these as "other forms of constant
expressions" which the C standard allows.
Rich Felker 1 éve
szülő
commit
0e330722c3
1 módosított fájl, 2 hozzáadás és 2 törlés
  1. 2 2
      src/math/sqrtl.c

+ 2 - 2
src/math/sqrtl.c

@@ -205,7 +205,7 @@ long double sqrtl(long double x)
 	top = (top + 0x3fff) >> 1;
 
 	/* r ~ 1/sqrt(m) */
-	static const uint64_t three = 0xc0000000;
+	const uint64_t three = 0xc0000000;
 	uint64_t r, s, d, u, i;
 	i = (ix.hi >> 42) % 128;
 	r = (uint32_t)__rsqrt_tab[i] << 16;
@@ -227,7 +227,7 @@ long double sqrtl(long double x)
 	r = mul64(u, r) << 1;
 	/* |r sqrt(m) - 1| < 0x1.c001p-59, switch to 128bit */
 
-	static const u128 threel = {.hi=three<<32, .lo=0};
+	const u128 threel = {.hi=three<<32, .lo=0};
 	u128 rl, sl, dl, ul;
 	rl.hi = r;
 	rl.lo = 0;