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don't suppress sign output for NANs in printf

formally, it seems a sign is only required when the '+' modifier
appears in the format specifier, in which case either '+' or '-' must
be present in the output. but the specification is written such that
an optional negative sign is part of the output format anyway, and the
simplest approach to fixing the problem is removing the code that was
suppressing the sign.
Rich Felker vor 10 Jahren
Ursprung
Commit
0f859fc993
1 geänderte Dateien mit 1 neuen und 1 gelöschten Zeilen
  1. 1 1
      src/stdio/vfprintf.c

+ 1 - 1
src/stdio/vfprintf.c

@@ -225,7 +225,7 @@ static int fmt_fp(FILE *f, long double y, int w, int p, int fl, int t)
 
 	if (!isfinite(y)) {
 		char *s = (t&32)?"inf":"INF";
-		if (y!=y) s=(t&32)?"nan":"NAN", pl=0;
+		if (y!=y) s=(t&32)?"nan":"NAN";
 		pad(f, ' ', w, 3+pl, fl&~ZERO_PAD);
 		out(f, prefix, pl);
 		out(f, s, 3);