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in synccall, ignore the signal before any threads' signal handlers return

this protects against deadlock from spurious signals (e.g. sent by
another process) arriving after the controlling thread releases the
other threads from the sync operation.
Rich Felker 11 년 전
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3c0501d28c
1개의 변경된 파일4개의 추가작업 그리고 4개의 파일을 삭제
  1. 4 4
      src/thread/synccall.c

+ 4 - 4
src/thread/synccall.c

@@ -71,6 +71,10 @@ void __synccall(void (*func)(void *), void *ctx)
 	sigqueue(self->pid, SIGSYNCCALL, (union sigval){0});
 	while (sem_wait(&chaindone));
 
+	sa.sa_flags = 0;
+	sa.sa_handler = SIG_IGN;
+	__libc_sigaction(SIGSYNCCALL, &sa, 0);
+
 	for (cur=head; cur; cur=cur->next) {
 		sem_post(&cur->sem);
 		while (sem_wait(&cur->sem2));
@@ -82,10 +86,6 @@ void __synccall(void (*func)(void *), void *ctx)
 		sem_post(&cur->sem);
 	}
 
-	sa.sa_flags = 0;
-	sa.sa_handler = SIG_IGN;
-	__libc_sigaction(SIGSYNCCALL, &sa, 0);
-
 	__syscall(SYS_rt_sigprocmask, SIG_SETMASK,
 		&oldmask, 0, _NSIG/8);