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Эх сурвалжийг харах

in synccall, ignore the signal before any threads' signal handlers return

this protects against deadlock from spurious signals (e.g. sent by
another process) arriving after the controlling thread releases the
other threads from the sync operation.
Rich Felker 11 жил өмнө
parent
commit
3c0501d28c
1 өөрчлөгдсөн 4 нэмэгдсэн , 4 устгасан
  1. 4 4
      src/thread/synccall.c

+ 4 - 4
src/thread/synccall.c

@@ -71,6 +71,10 @@ void __synccall(void (*func)(void *), void *ctx)
 	sigqueue(self->pid, SIGSYNCCALL, (union sigval){0});
 	while (sem_wait(&chaindone));
 
+	sa.sa_flags = 0;
+	sa.sa_handler = SIG_IGN;
+	__libc_sigaction(SIGSYNCCALL, &sa, 0);
+
 	for (cur=head; cur; cur=cur->next) {
 		sem_post(&cur->sem);
 		while (sem_wait(&cur->sem2));
@@ -82,10 +86,6 @@ void __synccall(void (*func)(void *), void *ctx)
 		sem_post(&cur->sem);
 	}
 
-	sa.sa_flags = 0;
-	sa.sa_handler = SIG_IGN;
-	__libc_sigaction(SIGSYNCCALL, &sa, 0);
-
 	__syscall(SYS_rt_sigprocmask, SIG_SETMASK,
 		&oldmask, 0, _NSIG/8);