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in synccall, ignore the signal before any threads' signal handlers return

this protects against deadlock from spurious signals (e.g. sent by
another process) arriving after the controlling thread releases the
other threads from the sync operation.
Rich Felker пре 11 година
родитељ
комит
3c0501d28c
1 измењених фајлова са 4 додато и 4 уклоњено
  1. 4 4
      src/thread/synccall.c

+ 4 - 4
src/thread/synccall.c

@@ -71,6 +71,10 @@ void __synccall(void (*func)(void *), void *ctx)
 	sigqueue(self->pid, SIGSYNCCALL, (union sigval){0});
 	while (sem_wait(&chaindone));
 
+	sa.sa_flags = 0;
+	sa.sa_handler = SIG_IGN;
+	__libc_sigaction(SIGSYNCCALL, &sa, 0);
+
 	for (cur=head; cur; cur=cur->next) {
 		sem_post(&cur->sem);
 		while (sem_wait(&cur->sem2));
@@ -82,10 +86,6 @@ void __synccall(void (*func)(void *), void *ctx)
 		sem_post(&cur->sem);
 	}
 
-	sa.sa_flags = 0;
-	sa.sa_handler = SIG_IGN;
-	__libc_sigaction(SIGSYNCCALL, &sa, 0);
-
 	__syscall(SYS_rt_sigprocmask, SIG_SETMASK,
 		&oldmask, 0, _NSIG/8);